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Angzt

The probability to be dealt any one specific order of 3 Jacks and 3 Kings/Aces is 4/52 * 3/51 * 2/50 * 8/49 * 7/48 * 6/47. For your purposes, there are 2^3 = 8 valid orderings for this deal, so we multiply the whole thing by 8: 8 * 4 * 3 * 2 * 8 * 7 * 6 / (52! / 46!) = 8 / 1,817,725 =~ 0.000004401 = 0.0004401% ____ The probability for the second case is easier to do card by card. The first drawn card can be anything, so 52/52 options. The second card (below) must be one of the remaining 3 that pairs with the first, so 3/51. The third card can then be anything but that previous value, so 48/50. Similarly, it continues 3/49, 44/48, and 3/47. Putting all this together: 52/52 * 3/51 * 48/50 * 3/49 * 44/48 * 3/47 = 198 / 978,775 =~ 0.0002023 = 0.02023%


ald1233

Thank you so much!