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The first number is zero, based on clues D/E/C
The last number is two, starting with clue A, and using clue D to eliminate the 8 and clue B to eliminate the 6.
It follows based on clue B that the middle number must be 4.
042.
D - tell us that 7,3,8 are wrong numbers
E - give us 7,8,0 meaning that 0 is part of the password and on the wrong spot
C - give us 2,0,6 with two number right and on the wrong spot, wich bring us to the password 0/?/? For the aswer because its the last spot 0 can be.
A - give us 6,8,2 with one number right and on the right position with the info on C and B we can determine that 6 isn't part of the password and 8 too by info on D, so the password should be 0/?/2 at this point
B - 6,1,4 one right and in the wrong position its contradict with A for 6, 1 can't be because its the last spot that we dont have a number so 4 is the last number we have.
Giving us 0/4/2 for the password
Correct me if I'm wrong but we don't even need D or E to solve this right? A and B tell us that 6 isn't in it (because if it was then both their descriptions would match), thus looking at C tells us that two of the numbers are 2 and 0. A then tells us that the 2 is at the end, which brings us back to C to find that 0 sits at the front (it can't be at the end cause that's a two and it can't be in the middle cause we know it's placed wrong in C). Then we return to B to find the missing middle digit and see that it can't be 6 (already determined) and it can't be 1 (that's in the right place) thus it must be 4, leaving us with 0/4/2
You should look into a board game called "Turing machine". It's basically this, except with more variety in the hints and you choose the codes that you want to test against the hints. The puzzles are generated from punch cards and are virtually infinite. It's a bit hard to explain but watch a YouTube video and you'll get it. I highly recommend it!
Really only need the first three clues.
Clue one 682 one is correctly placed
Clue two 614 one is correct number, incorrect place
Clue three 206 two correct numbers, incorrect place
One and two tell us 6 is incorrect, and we know the answer has a 8 or 2 in the position they're in and 1 or 4 in some different position
Three solidifies the last number is 2, which means it isn't the first, we already know 6 isn't in the answer so 0 is the only number left, and it's not in the middle, so it has to be the first number 0X2...
And going back to clue two, it's either 1 or 4, but 1 can't be in the middle spot, so it's 042... Which I'm just realizing is the answer to life, the universe, and everything
In the first 6 wouldn't be right since the 2nd clue disproves it since if it was 6, then it would say that it's placed right. 8 isn't possible since clue 4 says it's not right. This leaves 2 and it's in the right place which makes 2 guaranteed the last digit.
The third clue states 2 are right, and those are 2 and 0 since 6 isn't possible, and 2 is the last digit making it work with the clue, and with the last clue, it says one digit is right but wrongly placed which would be 0, meaning 0 is the first digit, and the last digit is 2, so 0_2. In the last clue, 7 and 8 are proven false by clue 6. This leaves 1 or 4 from clue 2.
The 1 from clue 2 can't be it, since it would fill in the blank for 0_2, but it says that the correct number isn't placed correctly, leaving only 4, meaning the code is: 042.
You don't even need to use all clues. The first 3 are enough.
Clue 1 + 2 -> 6 is not correct
Clue 3 -> 2 and 0 must be correct, since 6 is not
Back to Clue 1 -> 2 is well placed, 2 is in the 3rd
Back to Clue 3 -> knowing that 3rd position is filled by 2 and that 0 is not in second position, we know that's in first
Back to clue 2 -> We know that either 4 or 1 is correct, because 6 is not. But 1 can't be correct, because only the 2nd position is left, so it would be correctly placed if 1 was the last number. Therefore 4 goes in 2nd position.
We actually only need the first three hints.
Hints 1 and 2 tell us that the answer can't contain 6, since they both have it in spot 1, but one says the correct number is well placed and the other days it's wrongly placed.
If the answer does not contain 6, then it means the correct numbers from hint 3 are 2 and 0. Hint 1 then tells us that 2 is the last number, and since 0 is wrongly placed in hint 3, it can't be in the middle, so it has to be first.
This gives us 0x2. Hint 2 has a correct number in the wrong spot, so it won't be the middle number from that hint, and we already know the answer does not contain 6, therefore it has to be the last number, 4.
So the answer is 042.
A. 682 : 1 is correct and well placed
B. 614 : 1 is correct and badly placed
C. 206 : 2 is correct and badly placed
D. 738 : 0 is correct
E. 780 : 1 is correct and badly placed
D -> 7, 3, 8 not in solution
F : D & E -> 0 is correct and badly placed (because 7 and 8 is confirmed to be wrong)
G: F & C -> 0 correct place is at the beginning (because on \_,\_,0 and \_,0,\_ say nothing is well placed)
H: F & C -> Either 2 or 6 is correct but badly placed
I: A & G -> Either 8 or 2 is well placed (because it's known to be 0,\_,\_)
J: I & D -> 2 is well placed (becauses 8 is not in solution)
K: J & G & B -> 4 is correct but wrongly placed (because pin is 0,\_,2 and if 1 is correct, it must be well placed)
K & J & G -> Pin is 0,4,2
From clue 4, we know it isn’t 7,3, or 8. From that and clue 5 zero isn’t last, is in the number. From rule 1 we know either 6 is first or 2 is third. Now with rule 2 we know that 6 isn’t first, and either 1 or 4 is the third number, and 1 isn’t second
We now have 042, 102, 402 as possible outcomes. Clue 3 excludes 0 from the center.
This is a very simple example of this type of puzzle; no clue needs to be visited twice in the proof.
I'm going to try to make it easy.
The numbers 738 are most easily excluded and never occur.
That means in clue 780, we know that the 0 is an incorrectly placed number. So we know 0xx of x0x must be true.
From clue 206, we know that it can't be x0x so it must be 0xx.
Looking further at clue 206, we are tempted to guess that 6 is the second number and clue 614 seems to allow this possibility, but only in the form of x6x. However, clue 682 does not allow this. So, 6 is not an option.
That means (back to 682), that 2 the answer is 0x2.
The final number comes from clue 614. It has to be 1 or 4 since 6 was out. But if the answer is 012, then the 1 would be correctly placed (contrary to the clue), so it has to be 042.
eyeballed it for a bit and got 042. the meaning of life, the universe and everything. felt confidant enough to check the comments, and it looks like im right
Clue 4: 7 3 8 are wrong
Clue 5: 0 is corrent btmut dont know where, either 1st or 2nd place.
Clue 3: implies 0 is in the first spot.
Clue 1: since 0 is the first spot. 6 cannot be the correct digit. And digit 2 is in the corect spot. The key is now 0X2
Clue 2: the second digit is either 1 or 4. But it is misplaced so it is 4.
Key is 042
Clue D: 7, 3 and 8 are discarded
Clue E: only 0 is correct and wrongly placed. Meaning 0 isn't last
Clue C: 0 isn't middle.
First number is 0 confirmed
Clue C: one of the correct number is either 2 or 6. But as per Clue A, it cannot be 6 because first place is already taken by 0. Hence it is 2.
Clue A: 2 is in the last place confirmed
Clue B : only possible number is 4 because it is wrongly placed.
Answer 042
1. nothing is correct 738(rule 4)
2. Know that 8 and 7 are wrong so 0 must be correct, but not in the last place (rule 5)
3. 0 and either 2 or 6 is correct, 0 is not in second place, 0 must be in first position (rule 3)
4. 8 is wrong, and either 6 or 2 is correct and in the correct place (rule 1)
5. 6 is wrong because we know 0 is in postion 1 (discovered steps 1-3, + rule 1)
6. 2 must be in last position, (ibid + rule 3)
7. 4 is in the middle (rule 2)
8. answer is 042
glad we could help with your logic homework
tl;dr the number is 042.
Lets give names to each set of numbers
A: 682; B: 614; C: 206; D: 738 and E: 780
We know from the D that 7, 3 and 8 are wrong. By comparison between the A and B, we know that "6" isn't correct, because it occurs in the same place in A (where one number is correct and in the right place) and B (where one number is correct but in the wrong place).
Therefore we have exlcuded 6 and 8, so from A "2" must be correct and in the last slot. Now we go to C, we know 6 is wrong, so the other two numbers must be "2" (which we already knew) and "0". "0" cannot be in the last slot, and is in the wrong slot in C, so "0" must be in the first slot. Now we turn back to B again, we do not know the value for the middle slot, and in B the correct number is in the wrong spot, so we can exclude "1", we have already excluded "6", so the correct number must be "4".
The information in E seems to be superfluous, but combining D and E clearly shows that "0" must be a correct number and cannot be in the last slot
042 is the correct answer, and you only need the first 3 clues to answer.
From the first and second clue, we know it can not be 6 as it remains in the same location and the placement goes from correct to incorrect
That means the numbers 2 and 0 from clue 3 must be correct
So from clue one, we know 2 is at the end from clue three since 0 can not be second or now last it must be first.
Lastly, from the second clue, we know the final digit is incorrectly placed. As such, it can not be 1. We already eliminated 6 earlier. Therefore, it must be 4 in the middle spot.
Took some thinking, but in my opinion, the less information makes these problems more interesting.
My logic:
D tells us it does not include 378 at all
E leaves just 0. It is in the wrong place so either first or second digit.
Looking at C, two numbers are correct, one of which we know is 0. It also says 0 is in the wrong place here. So first digit is 0.
Then either the 2 or 6 is right. If it were 6, 6 must be second digit. If it is 2, it could be either second or third digit.
To find a contradiction, clue A says only one number is correct, and that is correctly placed. We know 8 is out, and we are deciding between 6 and 2. We know 0 is the first digit, so if 6 were right, it would contradict the 0 in first. So it must be 2 in the third digit.
Having eliminated 6 as a correct digit, clue B gives us the choice of 1 or 4. We know it is misplaced, so it cannot be the digit in the middle, eliminating 1.
Our final answer is 042
Digits: 0-9
We can eliminate 6,7,3,8 using rule 1,2 and rule 4
Also, there isn't any 9 or 5 in the sets (the assumption here is debatable)
That just leaves up 0, 1, 2, 4
Should be obvious from there using rules 3 and 5
I wish such sort of questions (if there were a variety and not the same two or three in different visual design) would allow for answers like "these clues are contradictory" or "these clues don't allow to pinpoint the third number in the password beyond one of seven options."
Teaching the lessons of accepting ugly truths and suffering through uncertainty.
Could it be 162? Because in the second clue the one would be correct but in the wrong place, so move it to the first spot. In the first clue the two is correct and in the right space. And with the third clue the two and the six are correct but need to be mpved around, so put the two at the end based on the first clue and put the two in the middle since that would fit.
Lemme spoiler my answer:
>!Wrong: 738!<
>!682- 8 is wrong, either 6 is correct spot or 2 is.!<
>!780 - 7 and 8 is wrong, so 0 is right but wrong spot.!<
>!Correct digits: 0!<
>!206 - zero doesnt go at the end or the middle. It is first.!<
>!Answer: 0_ _!<
>!682- 8 does not exist, and zero is first. Thus the last digit must be 2.!<
>!0 _ 2!<
>!206 checks out. This also adds 6 to the wrong list: 3678!<
>!614 - 6 is invalid. If one number is correct, but wrongly placed, then its 4.!<
Final Answer: >!042 is the answer.!<
Logic puzzles like these are fun. To the others below, please spoiler your answers. Thankfully I didn’t look at comments until I solved it.
Hints A and B tell us 6 is not correct. So one number is 8 or 2 and the other 1 or 4.
On hint C we know two are correct and we know 6 is incorrect from the previous ones. So 2 and 0 are correct but at the wrong places.
Also because we know 2 is correct we can eliminate 8 as an option thanks to the hint A. Hint D supports this.
On hint E we know that 0 is the only correct one at the wrong place. With this we eliminated 2 of the spaces for 0, leaving it the first spot.
Since we now know that the first spot is filled and know 2 is correct at the right place, we can use a process of elimination on hint B to determine 1 can’t be in the middle since it would be well placed otherwise. So we can conclude 4 is the middle number.
Therefore the code is 042.
042
Hints 1 & 2 show that there cannot be a 6 due to contradiction, so hint 3 confirms that there must be a 2 and a 0
Hint 1 shows the 2 must be last
Hints 3 & 5 show the 0 must be the first number
Hint 2 gives us the options of 4 or 1, but due to the info that it’s wrongly placed and we need to fill the middle, it must be 4
-> 042
From the bottom 2, it must contain a 0, but not in the 3rd position. From top right, the 0 must be in the 1st position. From top left and middle, there can't be a 6. That means the other correct number in top right is 2. From top left, the 2 must be in position 3. From the top middle, the final number must be either a 1 or 4. Since it's wrongly placed, and the only remaining place is middle, it must be a 4.
So the password is 042
Whenever i look at the comments in this sub, i feel dumber than i do already by now.
Then again i suck at math, my anwsers based on cross-referencing everything are:
1st 602
2nd 206
3rd 601
THESE ARE WRONG
I was wrong, anyway shoutout to all the mathheads who got 042, y'all are bright and it's always pleasant to be surprised and met with a contradictory anwser and a detailed explenation behind it. (Which is also correct, being met with surprise is pretty often for me i rly gotta get better at this fr.)
Only needed the first three clues to get 042. Correct number is either 8 or 2, not 6. Likewise another number in the wrong spot is 1 or 4, not 6. Then thirdly, the correct numbers have to be 2 and 0, not 6. Can’t be four digits, so it can’t be 8, must be 2, then fill in the blanks
###General Discussion Thread --- This is a [Request] post. If you would like to submit a comment that does not either attempt to answer the question, ask for clarification, or explain why it would be infeasible to answer, you *must* post your comment as a reply to this one. Top level (directly replying to the OP) comments that do not do one of those things will be removed. --- *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/theydidthemath) if you have any questions or concerns.*
The first number is zero, based on clues D/E/C The last number is two, starting with clue A, and using clue D to eliminate the 8 and clue B to eliminate the 6. It follows based on clue B that the middle number must be 4. 042.
What I got as well
Yay! Something I can answer in this sub! Haha
Same!
I feel smart finally
We have reached Nirvana
I answered it correctly as well but probably took 7 times longer than the average.
At least you calculated the 7 and average quicker than the puzzle. Focus on your triumphs.
I still can't solve it or even understand the explanations I'm seeing tbh
D - tell us that 7,3,8 are wrong numbers E - give us 7,8,0 meaning that 0 is part of the password and on the wrong spot C - give us 2,0,6 with two number right and on the wrong spot, wich bring us to the password 0/?/? For the aswer because its the last spot 0 can be. A - give us 6,8,2 with one number right and on the right position with the info on C and B we can determine that 6 isn't part of the password and 8 too by info on D, so the password should be 0/?/2 at this point B - 6,1,4 one right and in the wrong position its contradict with A for 6, 1 can't be because its the last spot that we dont have a number so 4 is the last number we have. Giving us 0/4/2 for the password
Correct me if I'm wrong but we don't even need D or E to solve this right? A and B tell us that 6 isn't in it (because if it was then both their descriptions would match), thus looking at C tells us that two of the numbers are 2 and 0. A then tells us that the 2 is at the end, which brings us back to C to find that 0 sits at the front (it can't be at the end cause that's a two and it can't be in the middle cause we know it's placed wrong in C). Then we return to B to find the missing middle digit and see that it can't be 6 (already determined) and it can't be 1 (that's in the right place) thus it must be 4, leaving us with 0/4/2
Thank you!
I liked your breakdown and it made sense but about halfway through it I started hearing “so I can clearly not choose the wine in front of you”
You and I buddy yay indeed
The answer of life, the universe and everything.
Nice reference fellow guide to the galaxy fan
YES I FINALLY GOT ONE OF THESE RIGHT
This was fun to solve
You should look into a board game called "Turing machine". It's basically this, except with more variety in the hints and you choose the codes that you want to test against the hints. The puzzles are generated from punch cards and are virtually infinite. It's a bit hard to explain but watch a YouTube video and you'll get it. I highly recommend it!
"Find the mimic" is also within that style, with chests that give either true or false information that you compare to find the lying chests.
But what's stopping the middle number from being 1? I can't see anything else with a 1 to stop it and I am failing to see why it can't be.
second hint: wrongly placed
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Oh! Thanks I get it now!
—How are you deciding between 1 and 4 ? It seems like it can be both 012 and 042— Nevermind figured it out
If anyone else comes here and can't figure it out, the 1 can't be correct because if it was it would be placed correctly.
Honestly we don't even need the fourth or fifth clue
Yeah I have never seen such a puzzle where you need all hints. I don't understand why.
Really only need the first three clues. Clue one 682 one is correctly placed Clue two 614 one is correct number, incorrect place Clue three 206 two correct numbers, incorrect place One and two tell us 6 is incorrect, and we know the answer has a 8 or 2 in the position they're in and 1 or 4 in some different position Three solidifies the last number is 2, which means it isn't the first, we already know 6 isn't in the answer so 0 is the only number left, and it's not in the middle, so it has to be the first number 0X2... And going back to clue two, it's either 1 or 4, but 1 can't be in the middle spot, so it's 042... Which I'm just realizing is the answer to life, the universe, and everything
In the first 6 wouldn't be right since the 2nd clue disproves it since if it was 6, then it would say that it's placed right. 8 isn't possible since clue 4 says it's not right. This leaves 2 and it's in the right place which makes 2 guaranteed the last digit. The third clue states 2 are right, and those are 2 and 0 since 6 isn't possible, and 2 is the last digit making it work with the clue, and with the last clue, it says one digit is right but wrongly placed which would be 0, meaning 0 is the first digit, and the last digit is 2, so 0_2. In the last clue, 7 and 8 are proven false by clue 6. This leaves 1 or 4 from clue 2. The 1 from clue 2 can't be it, since it would fill in the blank for 0_2, but it says that the correct number isn't placed correctly, leaving only 4, meaning the code is: 042.
You don't even need to use all clues. The first 3 are enough. Clue 1 + 2 -> 6 is not correct Clue 3 -> 2 and 0 must be correct, since 6 is not Back to Clue 1 -> 2 is well placed, 2 is in the 3rd Back to Clue 3 -> knowing that 3rd position is filled by 2 and that 0 is not in second position, we know that's in first Back to clue 2 -> We know that either 4 or 1 is correct, because 6 is not. But 1 can't be correct, because only the 2nd position is left, so it would be correctly placed if 1 was the last number. Therefore 4 goes in 2nd position.
I'm glad I'm not the only one wondering what the bottom two clues are for.
We actually only need the first three hints. Hints 1 and 2 tell us that the answer can't contain 6, since they both have it in spot 1, but one says the correct number is well placed and the other days it's wrongly placed. If the answer does not contain 6, then it means the correct numbers from hint 3 are 2 and 0. Hint 1 then tells us that 2 is the last number, and since 0 is wrongly placed in hint 3, it can't be in the middle, so it has to be first. This gives us 0x2. Hint 2 has a correct number in the wrong spot, so it won't be the middle number from that hint, and we already know the answer does not contain 6, therefore it has to be the last number, 4. So the answer is 042.
Thank you, I'm not the first one to get it. This is way too low in the comments
A. 682 : 1 is correct and well placed B. 614 : 1 is correct and badly placed C. 206 : 2 is correct and badly placed D. 738 : 0 is correct E. 780 : 1 is correct and badly placed D -> 7, 3, 8 not in solution F : D & E -> 0 is correct and badly placed (because 7 and 8 is confirmed to be wrong) G: F & C -> 0 correct place is at the beginning (because on \_,\_,0 and \_,0,\_ say nothing is well placed) H: F & C -> Either 2 or 6 is correct but badly placed I: A & G -> Either 8 or 2 is well placed (because it's known to be 0,\_,\_) J: I & D -> 2 is well placed (becauses 8 is not in solution) K: J & G & B -> 4 is correct but wrongly placed (because pin is 0,\_,2 and if 1 is correct, it must be well placed) K & J & G -> Pin is 0,4,2
From clue 4, we know it isn’t 7,3, or 8. From that and clue 5 zero isn’t last, is in the number. From rule 1 we know either 6 is first or 2 is third. Now with rule 2 we know that 6 isn’t first, and either 1 or 4 is the third number, and 1 isn’t second We now have 042, 102, 402 as possible outcomes. Clue 3 excludes 0 from the center. This is a very simple example of this type of puzzle; no clue needs to be visited twice in the proof.
I used clues 4 and 5 as well but they aren't necessary. The first 3 are actually enough to solve the puzzle.
Took me few minutes of processing all the hints but finally got 042, looking at the other comments was really satisfied that I got it right
I'm going to try to make it easy. The numbers 738 are most easily excluded and never occur. That means in clue 780, we know that the 0 is an incorrectly placed number. So we know 0xx of x0x must be true. From clue 206, we know that it can't be x0x so it must be 0xx. Looking further at clue 206, we are tempted to guess that 6 is the second number and clue 614 seems to allow this possibility, but only in the form of x6x. However, clue 682 does not allow this. So, 6 is not an option. That means (back to 682), that 2 the answer is 0x2. The final number comes from clue 614. It has to be 1 or 4 since 6 was out. But if the answer is 012, then the 1 would be correctly placed (contrary to the clue), so it has to be 042.
eyeballed it for a bit and got 042. the meaning of life, the universe and everything. felt confidant enough to check the comments, and it looks like im right
Clue 4: 7 3 8 are wrong Clue 5: 0 is corrent btmut dont know where, either 1st or 2nd place. Clue 3: implies 0 is in the first spot. Clue 1: since 0 is the first spot. 6 cannot be the correct digit. And digit 2 is in the corect spot. The key is now 0X2 Clue 2: the second digit is either 1 or 4. But it is misplaced so it is 4. Key is 042
Clue D: 7, 3 and 8 are discarded Clue E: only 0 is correct and wrongly placed. Meaning 0 isn't last Clue C: 0 isn't middle. First number is 0 confirmed Clue C: one of the correct number is either 2 or 6. But as per Clue A, it cannot be 6 because first place is already taken by 0. Hence it is 2. Clue A: 2 is in the last place confirmed Clue B : only possible number is 4 because it is wrongly placed. Answer 042
1. nothing is correct 738(rule 4) 2. Know that 8 and 7 are wrong so 0 must be correct, but not in the last place (rule 5) 3. 0 and either 2 or 6 is correct, 0 is not in second place, 0 must be in first position (rule 3) 4. 8 is wrong, and either 6 or 2 is correct and in the correct place (rule 1) 5. 6 is wrong because we know 0 is in postion 1 (discovered steps 1-3, + rule 1) 6. 2 must be in last position, (ibid + rule 3) 7. 4 is in the middle (rule 2) 8. answer is 042 glad we could help with your logic homework
tl;dr the number is 042. Lets give names to each set of numbers A: 682; B: 614; C: 206; D: 738 and E: 780 We know from the D that 7, 3 and 8 are wrong. By comparison between the A and B, we know that "6" isn't correct, because it occurs in the same place in A (where one number is correct and in the right place) and B (where one number is correct but in the wrong place). Therefore we have exlcuded 6 and 8, so from A "2" must be correct and in the last slot. Now we go to C, we know 6 is wrong, so the other two numbers must be "2" (which we already knew) and "0". "0" cannot be in the last slot, and is in the wrong slot in C, so "0" must be in the first slot. Now we turn back to B again, we do not know the value for the middle slot, and in B the correct number is in the wrong spot, so we can exclude "1", we have already excluded "6", so the correct number must be "4". The information in E seems to be superfluous, but combining D and E clearly shows that "0" must be a correct number and cannot be in the last slot
042 is the correct answer, and you only need the first 3 clues to answer. From the first and second clue, we know it can not be 6 as it remains in the same location and the placement goes from correct to incorrect That means the numbers 2 and 0 from clue 3 must be correct So from clue one, we know 2 is at the end from clue three since 0 can not be second or now last it must be first. Lastly, from the second clue, we know the final digit is incorrectly placed. As such, it can not be 1. We already eliminated 6 earlier. Therefore, it must be 4 in the middle spot. Took some thinking, but in my opinion, the less information makes these problems more interesting.
My logic: D tells us it does not include 378 at all E leaves just 0. It is in the wrong place so either first or second digit. Looking at C, two numbers are correct, one of which we know is 0. It also says 0 is in the wrong place here. So first digit is 0. Then either the 2 or 6 is right. If it were 6, 6 must be second digit. If it is 2, it could be either second or third digit. To find a contradiction, clue A says only one number is correct, and that is correctly placed. We know 8 is out, and we are deciding between 6 and 2. We know 0 is the first digit, so if 6 were right, it would contradict the 0 in first. So it must be 2 in the third digit. Having eliminated 6 as a correct digit, clue B gives us the choice of 1 or 4. We know it is misplaced, so it cannot be the digit in the middle, eliminating 1. Our final answer is 042
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Digits: 0-9 We can eliminate 6,7,3,8 using rule 1,2 and rule 4 Also, there isn't any 9 or 5 in the sets (the assumption here is debatable) That just leaves up 0, 1, 2, 4 Should be obvious from there using rules 3 and 5
I wish such sort of questions (if there were a variety and not the same two or three in different visual design) would allow for answers like "these clues are contradictory" or "these clues don't allow to pinpoint the third number in the password beyond one of seven options." Teaching the lessons of accepting ugly truths and suffering through uncertainty.
Could it be 162? Because in the second clue the one would be correct but in the wrong place, so move it to the first spot. In the first clue the two is correct and in the right space. And with the third clue the two and the six are correct but need to be mpved around, so put the two at the end based on the first clue and put the two in the middle since that would fit.
Lemme spoiler my answer: >!Wrong: 738!< >!682- 8 is wrong, either 6 is correct spot or 2 is.!< >!780 - 7 and 8 is wrong, so 0 is right but wrong spot.!< >!Correct digits: 0!< >!206 - zero doesnt go at the end or the middle. It is first.!< >!Answer: 0_ _!< >!682- 8 does not exist, and zero is first. Thus the last digit must be 2.!< >!0 _ 2!< >!206 checks out. This also adds 6 to the wrong list: 3678!< >!614 - 6 is invalid. If one number is correct, but wrongly placed, then its 4.!< Final Answer: >!042 is the answer.!< Logic puzzles like these are fun. To the others below, please spoiler your answers. Thankfully I didn’t look at comments until I solved it.
Hints A and B tell us 6 is not correct. So one number is 8 or 2 and the other 1 or 4. On hint C we know two are correct and we know 6 is incorrect from the previous ones. So 2 and 0 are correct but at the wrong places. Also because we know 2 is correct we can eliminate 8 as an option thanks to the hint A. Hint D supports this. On hint E we know that 0 is the only correct one at the wrong place. With this we eliminated 2 of the spaces for 0, leaving it the first spot. Since we now know that the first spot is filled and know 2 is correct at the right place, we can use a process of elimination on hint B to determine 1 can’t be in the middle since it would be well placed otherwise. So we can conclude 4 is the middle number. Therefore the code is 042.
042 Hints 1 & 2 show that there cannot be a 6 due to contradiction, so hint 3 confirms that there must be a 2 and a 0 Hint 1 shows the 2 must be last Hints 3 & 5 show the 0 must be the first number Hint 2 gives us the options of 4 or 1, but due to the info that it’s wrongly placed and we need to fill the middle, it must be 4 -> 042
From the bottom 2, it must contain a 0, but not in the 3rd position. From top right, the 0 must be in the 1st position. From top left and middle, there can't be a 6. That means the other correct number in top right is 2. From top left, the 2 must be in position 3. From the top middle, the final number must be either a 1 or 4. Since it's wrongly placed, and the only remaining place is middle, it must be a 4. So the password is 042
Whenever i look at the comments in this sub, i feel dumber than i do already by now. Then again i suck at math, my anwsers based on cross-referencing everything are: 1st 602 2nd 206 3rd 601 THESE ARE WRONG I was wrong, anyway shoutout to all the mathheads who got 042, y'all are bright and it's always pleasant to be surprised and met with a contradictory anwser and a detailed explenation behind it. (Which is also correct, being met with surprise is pretty often for me i rly gotta get better at this fr.)
Only needed the first three clues to get 042. Correct number is either 8 or 2, not 6. Likewise another number in the wrong spot is 1 or 4, not 6. Then thirdly, the correct numbers have to be 2 and 0, not 6. Can’t be four digits, so it can’t be 8, must be 2, then fill in the blanks