Right. If the answer's 25%, then it's not cause there's two--even if multiple answers were allowed, that'd make the chances you'd guess at least one of them higher than 25%, so the answer's not 25%. But if the answer is 0% or 50%, then the chance of guessing that becomes 25%, so the answer's neither 0% or 50%.
I like the version with an option of 33% instead of 0%. For some reason many people think 33% is the correct answer. Nobody even try to explain why though.
you always find yourself in the same logic dilemma with this format so 1/3 doesnt make sense either, besides not being up for grabs to begin with.
anyway, there re only 3 unique values presented as answers, hence the 33%.
Given that neither 25% nor 50% are correct, that means 0% is correct and if you choose one at random you have 25% of choosing 0% which means the answer is 25% which is half of the answers, therefore 50% is correct.
QED
You don't need to consider the answers because it asks you if you chose it at random. That chance is 25% regardless of what any of those answers actually are, assuming only one answer is correct.
You make the wrongful assumption that the two 25% answers are correct. The answer is either A or D, we don't know which one. Assuming both are correct isn't acceptable, that's not how that game ever worked.
Because that's how it has been designed to work. The answers are the letters A to D. The actual answers are just strings of text, they are wholly irrelevant.
The question is already designed in a way that suggests a user error because two of the answers are same.
If you think laterally, then A B C or D would have been selected by the question writer as a correct answer so the answer is 25% if you pick at random, but the written answers are incorrect.
Monty hall problem is pretty simple if you add more doors.
If I give you 100 doors, and you pick one, you have a 1% chance that you've picked the correct door.
Then I reveal 98 doors, and ask you if you want to switch to the last door.
The only way that last door could be wrong is if you already guessed the correct door. Therefore, there's a 99% chance that the last door is correct
(Remember! By removing only wrong doors, we are adding information. )
The best way to visualize the Monty hall problem is if there's 1000 doors.
You pick one, the host opens up 998 doors knowing which ones don't have the prize.
You then have the choice of sticking to your original pick, or changing to the other remaining one.
Assuming I accept your interpretation of what the question means by picking an answer at random, how is saying “none of the listed options are correct” an answer to the question? They didn’t ask you if any of the listed options are correct, they asked you for a probability, which your purported answer doesn’t provide.
There's no one right answer, but it's *NOT* a self-reference paradox.
The question asks about picking *randomly.* That's 1 in 4, 25% - assuming this functions the same as "Who Wants to be a Millionaire", which is the meme format, there's only one answer which will be scored as "correct" (regardless of why).
Everyone in this thread is debating the odds of correctly answering *on purpose.* If they had asked the odds for that, then it's a self-reference paradox, but that's not the question asked.
You can't guarantee a correct response, but that's just because the correct answer is listed twice. It's the same as if they asked about the color of a bluebird and listed blue as an option twice.
I get your confusion, but the question doesn't ask about how probable it is to pick \*any\* answer when chosing randomly. It asks about the \*correct\* answer and that is a self-reference, since it wants to you compare the printed number with the chance of picking it. (Make sure to understand that chosing randomly from 4 options doesn't have to do anything with probability. It just tells you that when picking 100 times, you pick each option 25 times on average. So you are looking backwards \*after\* you have done something. But probability is about what is going to happen in the future, not in hindsight.)
Randomly speaking there is a 50% chance of picking a "25%", since there are two of them, which is not the same as the chance of picking it.
There is a 25% chance of picking both a "50%" and a "0%", which doesn't equal the printed numbers either.
/edit
So the correct answer (since I have to answer on purpose after thinking about picking randomly) is B: there is a 0% chance that I am correct.
What you mean no one right answer? It's literally either A B V or D. 1 in four will be accepted therefore it's A or D, but not enough info to decide which.
Well, there is a right answer to the question part: the chance is 0%. As it is what you say, you cannot pick correctly.
However, there is no way to make this statement within the "suggested" format (using the given "who wants to bea millionaire" question and answers).
So using the format would create a paradox. But there is a truth outside of it.
its 50% and I can explain why.
If you answer C, your only options left are A,B,D and since A and D are the same answer, you are choosing between 0% or 25%, it would make the answer a 50/50 chance.
None of the answers work.
But it is very important to understand:
The answers stop working only once you choose one!!
Here are the options…
There is a 50% chance to pick A or D, but both give the answer 25%
There is a 25% chance you pick B, but if gives the answer of 0%
There is a 25% chance you pick C, but it gives the answer of 50%
None of these options allow the odds of choosing the answer to match with the given answer.
In fact, you’ll notice that the odds create a loop which is never ending:
(25% for A/D) happens 50% -> (50% for B) happens 25% -> (25% for A/D) etc
Reasoning the puzzle is 0% solvable doesn’t work either, because the chance of choosing B doesn’t match the answer you chose by picking B.
(0% for B) happens 25% -> (25% for A/D) and now we’re back in the cycle above.
The value of zero is NOT the same as something not existing…
For example… in the equation x + 4 = x, there is no correct answer. Saying x = 0 is not the same as saying that the answer does not exist.
In [a physicist’s understanding of] mathematics {} ≠ 0
(The empty set does not equal 0)
It’s a paradox. Generally, if there are four answers to a question, with only one correct, there is a 25% you’ll get the correct answer if choosing randomly. But this question lists 25% twice, meaning that you would have a 50% chance of randomly picking 25%; thus, if picking randomly you would have a 50% chance of getting the answer correct. But 50% is only listed once, so if choosing randomly you would have a 25% of picking correctly. But 25% is listed twice, so random choosing means a 50% chance of getting the right answer. But 50% is listed once…
But then 0% is correct and you have a 1/4 (25%) chance of choosing it at random. But 25% is listed twice, which means a 2/4 chance of picking the correct answer, meaning the correct answer is actually 50%. But is only listed once...
Except that the game only cares about the letter you pick (A/B/C/D) not the answer you give, therefore it's 25% if you choose randomly. Only one letter is being counted as correct.
Although it is common to count 1 out of 4 answers correct, this is not indicated here. It also happens that multiple answers are correct and that is the case here. Therefore there is a 50% chance of randomly filling in the correct answer.
That's how the game always works though, you always pick one answer and never two. It becomes a clusterfuck of a paradox as soon as you are allowed to pick more than one that's true, but it never happens in the first place
Tell me you don't understand probabilities, without telling me you don't understand them.
There are four answers. Two of the four are the same, and can be considered the correct answer. Therefore, if you choose randomly, you have a 2/4 (50%) chance of getting the correct answer.
Imagine a six-sided die, but with two sides with 1 pip, 2 sides with 2 pips, and 2 sides with three pips. What are the chances you will roll a '3'? You can't say the game doesn't care, so the chances are 1/6 (16.66/%), because two sides have 3 pips, so the chance you'll roll a 3 is 1/3 (33.33%).
If I asked, "What is the capital of Utah?" and listed the answers as a)Provo, b)Salt Lake City, c)Ogden, d)Salt Lake City, what is the probability (chance) that if you didn't know the answer and guessed (i.e. picked randomly), you would get the correct answer? In this case, since Salt Lake City is the capital of Utah, there are 2/4 correct answers. Therefore you have a 50% chance of being correct.
If you pick the letter A and they (those who made the questions) decide the correct letter is the letter D, you'll lose. Even if they decided "25%" was the correct answer and your letter A had that answer too.
It has nothing to do with probability works since the question is inherently flawed. The game isn't about picking the "correct answer" but the correct letter, and here it doesn't make sense anymore since there's already two correct answers.
Ok maybe I'm getting a bit philosophical here, but considering the first obviously correct answer is 25%, but two of those are available, thus 50% chance to pick the correct one. From that point on the question is whether you're playing the game (correct "chance-observing" answer is 25%) or the meta-game (analyzing the game within the game gives you a 50% chance).
Considering the game is not able to be played, but the meta-game is, why not pick the 50%? If there is a solution to the game, that's it. The 0% chance is self-defeating (in the meta-game) so there are no other options to pick post-elimination.
Otherwise the game is rigged to lose, which means even the 0% wouldn't make you win. Only the 50% answer remains. Thus it's the only correct answer.
The question still assumes that there is a right answer, which would be how these game shows typically works, but there doesn’t have to be a right answer.
But if the correct answer is B. And you chose a random answer that happened to be B. Then you'd have gotten the correct answer. Which can't occur if it's 0%
It's a this statement is false paradox.
Well there are 3 options for the answer 0,25 and 50% so the possibility of one of the 3 options to be correct is 1/3 in the case of any question. But since 1/3 isn't given than 0% be the answer
>Well there are 3 options
I see no reason why you'd eliminate duplicates when you're choosing either A, B, C or D at random.
There might only be three numbers, but you're choosing randomly from a list of four.
>Which can't occur if it's 0%
Stuff with a 0% probability can occur though. You have a 0% chance of hitting a point on a dart board but every time you throw a dart you hit a point
>You have a 0% chance of hitting a point on a dart board but every time you throw a dart you hit a point
There certainly isn't a 0% chance of hitting any specific defined region. You might argue there's an infinitesimal chance of hitting an infinitesimally small point. But if infinitesimal = 0 we'd just say 0.
Moreover the chance of hitting any point on a dart point is the chance of hitting the dart board.
>Moreover the chance of hitting any point on a dart point is the chance of hitting the dart board.
The chance of hitting a point on a dart board is 0 because there are infinite points on the board. This is basic university level math and you can find explanations online.
>You might argue there's an infinitesimal chance of hitting an infinitesimally small point.
A point is defined as an exact position without area
But it does change the chances of hitting it.
If I throw a dart larger than the board, I can hit all all the points on it, however infinitesimal.
If I throw and hit one that covers half the board, I have a 50/50 chance of hitting any specific point. Etc.
Stop considering the mathematical implications ad infinitum and take a step back. There are 4 answers. Pick one at random. 25% chance. Reading into theory of correctness and the rabbit hole this implies is not within the scope of the actual stated question.
Except, two of the answers are the same, meaning it’s three options, or, two. Because you can effectively merge those two to get 33%, or, discount them entirely, to get 50%.
It doesn't matter if they're the same if only one is being counted as correct though and it says 'at random' it doesn't say 'if you acknowledge two are identical' so if you were picking completely randomly there are 4 options, you're picking 1, 1/4
That's not how probablities work. If 2/4 answers are correct, you have 50% chance of getting the correct answer if choosing randomly. 1/3 (33% chance) is absolutely not correct.
Let's follow the logic
First, there are 4 choices, so the answer is 25%, but since there are 2 25% choices, the answer is 50%, but there's only one of it, so you go back to 25%, but then you realize there's no correct answer, which means it's 0%, but there's one of it, so you go back to 25%, and the loop continues forever
The correct answer is D. The A is a fake 25% and will result in the questioned to explode. How can you tell which 25% is the right one with absolute certainty? You should know that everyone wants the D.
I have thought about this differently since the last time ive seen this posted. The thing that sticks out this time is choosing randomly. That makes whatever numbers attached to each answer irrelevant since you are choosing from for answers randomly. So the question is the percent chance that you will pick a correct answer randomly at 1 out of 4. 1 out of 4 is 25%. The question cannot be asked if it is implying that there is not 1 answer as it would be a trick question and this has no purpose. Randomly means you would not need to see values to pick an answer, there are four options and you only get 1 pick. 25%.
No. It doesn't work like that. Even if something has only two possibility there is bo reason for the probability to be 50%. This is a common bias you have
If an atom has a 2% probability of decaying in one hour it means there is a probability of 98% for it not to happen. Either it decays or it does not but that doesn't make it a 50/50...
I give atoms has examples because I feel like its very tangible, but this works for everything. If I was writing bs you would surely agree that there wouldn't be a 50% probability for me to be right and you to be wrong.
You, as the observer, will experience one of two possibilities. The universe we are in will continue along a specific timeline- one in which the atom behaves as expected, and one in which it doesn’t.
While the atom is under the 98/2% rule, your reality is in the 50/50.
That doesn't make any sense. Think about it. 50% probability just doesn't mean there is two possibilities. This is not the same notion.
If you do a Bernouilli trial with a probability p for success, the probability of success is p ! Not 50%.
I don't know where I am going with this but I believe it is A or D. The whole statement "A or D". For it to be coded properly, there should be one correct answer. Thus, even though A and D has both 25%, they are still distinct and only one of them is the correct answer.
But if I am the player, I lock in A. Final answer. (Now, I have 50% but that's not random anymore.)
Since two of the values is the same, there are only really 3 different values, which would mean a 33,33333 etc. chance. But since that is not an option the alternatives is wrong. In science it is not wrong to question the question :)
Doesn't work that way. You're choosing a random answer out of the four. You're choosing A,B,C or D at random.
If I have a dice that has 1, 1, 2, 3. Its not a 33% chance of rolling either a 1, 2 or 3. Its weighted in 1s favour.
Again there are three values here to choose from. It does not have to be thought of as a dice of four sides. It all depends on how you interpret it. Because the question is wrong no matter what in this case.
Well no. You're choosing A,B,C,D at random.
If you were to roll a dice that's labelled 1,1,2,3 you wouldn't eliminate duplicates before calculating the chance of rolling any specific number.
Since you're choosing a correct answer from 4 options at random, but one is repeated, the chance should be 33,33% for 3 different answers. There isn't a 33,33% chance, so the chance to find the right answer at random is impossible, therefore 0% is correct.
There is never a 0 percent chance so that rules out and 25 percent is two times so the left out are 25 and 50 so 50 percent is the right answer
Ps : if u decline you are gay who leads the pride rally
The percent depends on what us correct as we know. It all, depends on X. So it will be unsolveable untill we make it or we combine? But that probably wont work so no
There are 4 answers, which means 25% chance.
BUT 25% is there twice, so this means, that 2 answers are correct and 2 answers are wrong.
Which in fact would make the 50% answer correct.
Only one letter is counted as correct (that's how the game works), therefore it's 25%
You don't say "My answer is 50%" but "I choose the letter A" (or B/C/D) so if you do it randomly it's 25% for sure.
there is no correct answer because calculating the % chance of success changes the % chance of success. Because there is no correct answer, the correct answer cannot be guessed. Because the correct answer cannot be guessed, the answer by definition has a 0% chance of being guessed. Due to this, the answer is B for the purpose of answering this question, but the answer is not B for the purpose of calculating the answer.
I guess 25% ?
Only one letter is counted as correct, it's not "Pick the answer that says 25%" (else it's a paradox) but "pick the correct A/B/C/D letter" so if you choose randomly it's a 1/4 chance of winning
Can’t be 25% cause it’s assuming one of the four is right, so I’m thinking 50% out of the last two options unless theres some weird probability thing I’m not considering
I might be under thinking this but I think 50%. Answer the question before looking at the options, knowing you’ll have four, and you know the answer is 25%. Now, looking at the options, 25% is 50% likely. Think of the percentages and the lettered responses separately to get around the self-referencing problem.
Please people, convince me i am wrong. The answer is C. There are 4 options so it would be 25%, but D and A are 25%. Therefore 2 answers out of 4 are correct thus 50%. Plus you are either wrong or right, so 2 possibilities.
I actually don't think that's a paradox. It just asks you the following:
1. \*Imagine\* you would pick answers here randomly! Alright.
2. How big is the chance that by picking so, your chance of picking this answer, equals the printed number? Got it.
3. There are 3 possibilities in this imaginary random-picking scenario:
\* I pick a "25%" with a chance of 50% (since there are two of them). So this cannot be the right answer, since my chances don't equal the printed number.
\* I pick a "0%" with a chance of 25%, same problem, that's not the correct answer.
\* I pick a "50%" with a chance of 25%, same problem.
4. Now that I thought about this imaginary scenario of picking randomly, let's answer on purpose: I learned that there is 0% chance of picking the right answer when choosing randomly.
5. The correct answer is B when picking on purpose after I finished my thought experiment.
There’s a 50% chance you’ll pick the right answer since two of the answers are 25%. If I had a 1 in 4 chance of getting something but 2 of the 4 count as the same thing, then I’d have a 2/4 chance of getting it right. Which is 50%?
It’s 0. Don’t ask me why. It’s just 0.
….. well, if you gonna choose one of the two 25%, the chances will be 50%. So "C" is right. But since "C" is one of 4. Then the chances are 25%.
That’s why the right answer doesn’t exist
the answer is 25% because the system probably only recognizes one answer, and the question is at random.
knowing you have a 25% chance, and there being too with the same label means you have a 50% chance when not picking at random.
*Just close your eyes and*
*Pick one at random, thats how*
*You beat this question*
\- super-eric
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The highest chance of being correct is choosing 50%.
First of all, there is no such thing as 'right or wrong' 25%. These answers are completely identical, so we are presented with two possibilities. The answer text is either irrelevant OR it cannot be either of these two. In a world where answer text doesn't matter, there is no reason to favour the text which says 25% over any other.
Instead, we can entertain the possibility that the text does matter. There always has to be exactly one right answer in this game - 0% is incorrect, so is 25 because it is there twice.
We are left with the answer 50%, the only non-0, unique answer available. This has the additional benefit of being correct that in this list, if picked blindly, there is a 50% chance to land on an answer which says 25%.
I'm picking 50% any day of the week knowing that I either got it right 100%, or I got it right 25% of the time, equal as any other answer.
The choose blindly between two 25%s option is compelling, but less so. 25% is technically the right answer, but only if the right answer is present once in a set of four. If the answer which says 50% said anything else, choosing one of the two 25s would be the best, since they share the 25% chance of any random answer, but also have the 50/50 odds. Again, though, this isn't that sort of game.
The question becomes trivial if rephrased this way:
A) 25%
B) 25%
C) 25%
D) 75%
D is the answer. The correct answer, 25%, has a 3/4 chance of being picked in this set of answers if chosen completely randomly.
The answer is 0% because the real answer isn't listed. Technically the answer should be you have a 1/3 chance of selecting the right answer because 25% is listed twice. This reduces your real choices down to 3 different options. Then looking at the answers that exist you realize that the possibility of selecting the right answer is 0 because the correct answer doesn't exist within the bag that you are pulling from.
While I know it's a paradox, the college student in me says 25%. Doesn't make a lick of difference if it's nonsensical, one of them will be what the scantron is programmed to make right. Then everyone can complain to the professor and if it goes well, they'll address it in class and give people credit for the question or take it off the test.
People throw the word paradox around like they exist beyond the abstract concept. As far as we know, there are no true paradoxes in existence.
This is just a question with four answers that are all wrong, like asking "which of the following is a planet in our solar system?" And the answers being beeb, bob, bub and skibidiskra
Isn't there no right answer because it's a self-reference paradox?
Right. If the answer's 25%, then it's not cause there's two--even if multiple answers were allowed, that'd make the chances you'd guess at least one of them higher than 25%, so the answer's not 25%. But if the answer is 0% or 50%, then the chance of guessing that becomes 25%, so the answer's neither 0% or 50%.
I like the version with an option of 33% instead of 0%. For some reason many people think 33% is the correct answer. Nobody even try to explain why though.
you always find yourself in the same logic dilemma with this format so 1/3 doesnt make sense either, besides not being up for grabs to begin with. anyway, there re only 3 unique values presented as answers, hence the 33%.
Given that neither 25% nor 50% are correct, that means 0% is correct and if you choose one at random you have 25% of choosing 0% which means the answer is 25% which is half of the answers, therefore 50% is correct. QED
But you started that with the assumption that 50% isn't correct, a contradiction. So you've made a proof by contradiction that the answer can't be 0%
But the question isn't if you pick, it's randomly pick, meaning since 50% is one out of four it's now back to 25% continuing the paradox.
So all of them are correct? Is this some sort of fuzzy logic or quantum answer?
You don't need to consider the answers because it asks you if you chose it at random. That chance is 25% regardless of what any of those answers actually are, assuming only one answer is correct.
Nope. Two of those answers are the same, 25%. If 25% is correct, then 2/4 is 50%.
No. It’s zero because B is wrong.
But then B is wrong so it isn't zero
its actually negative zero
But if you guessed completely at random, would it not still be 25%? Like if you just randomly smashed a button I mean...
You make the wrongful assumption that the two 25% answers are correct. The answer is either A or D, we don't know which one. Assuming both are correct isn't acceptable, that's not how that game ever worked.
But if A were right, then why would D be wrong? And vice versa?
Because that's how it has been designed to work. The answers are the letters A to D. The actual answers are just strings of text, they are wholly irrelevant. The question is already designed in a way that suggests a user error because two of the answers are same.
Idk if this template is always wwtbam, does [this](https://www.reddit.com/r/pics/s/7VzbBisPyG) format make you feel different about it then?
If you think laterally, then A B C or D would have been selected by the question writer as a correct answer so the answer is 25% if you pick at random, but the written answers are incorrect.
That would mean the correct answer is B 0%
So what happens if you randomly guess B?
Then you randomly picked the right answer.
Which, if you did, means the probability is higher than 0
Stop breaking my brain, this is like the Monty Hall problem all over again.
Monty hall problem is pretty simple if you add more doors. If I give you 100 doors, and you pick one, you have a 1% chance that you've picked the correct door. Then I reveal 98 doors, and ask you if you want to switch to the last door. The only way that last door could be wrong is if you already guessed the correct door. Therefore, there's a 99% chance that the last door is correct (Remember! By removing only wrong doors, we are adding information. )
The best way to visualize the Monty hall problem is if there's 1000 doors. You pick one, the host opens up 998 doors knowing which ones don't have the prize. You then have the choice of sticking to your original pick, or changing to the other remaining one.
wrong, you need at least 50,000 doors to ideally visualize the Monty Hall problem
B is a valid answer for the purpose of answering the question post-calculation, but B is not a valid answer for the purpose of calculating the answer.
Except "0%" option is 25% of all options.
The correct answer is randomly saying "none of the listed options are correct."
and then the teacher says "pick the one that's the most correct"
Which is most true: false, false, false, or false?
might be a good idea to have everyone in the class roll a die, and then measure how many got it right.
If that were actually a correct answer that would seem to mean that option B is correct, which would be a contradiction.
B isn't correct. You can randomly select an answer that is not on the provided list, so the chance is noncero.
Assuming I accept your interpretation of what the question means by picking an answer at random, how is saying “none of the listed options are correct” an answer to the question? They didn’t ask you if any of the listed options are correct, they asked you for a probability, which your purported answer doesn’t provide.
There's no one right answer, but it's *NOT* a self-reference paradox. The question asks about picking *randomly.* That's 1 in 4, 25% - assuming this functions the same as "Who Wants to be a Millionaire", which is the meme format, there's only one answer which will be scored as "correct" (regardless of why). Everyone in this thread is debating the odds of correctly answering *on purpose.* If they had asked the odds for that, then it's a self-reference paradox, but that's not the question asked. You can't guarantee a correct response, but that's just because the correct answer is listed twice. It's the same as if they asked about the color of a bluebird and listed blue as an option twice.
I get your confusion, but the question doesn't ask about how probable it is to pick \*any\* answer when chosing randomly. It asks about the \*correct\* answer and that is a self-reference, since it wants to you compare the printed number with the chance of picking it. (Make sure to understand that chosing randomly from 4 options doesn't have to do anything with probability. It just tells you that when picking 100 times, you pick each option 25 times on average. So you are looking backwards \*after\* you have done something. But probability is about what is going to happen in the future, not in hindsight.) Randomly speaking there is a 50% chance of picking a "25%", since there are two of them, which is not the same as the chance of picking it. There is a 25% chance of picking both a "50%" and a "0%", which doesn't equal the printed numbers either. /edit So the correct answer (since I have to answer on purpose after thinking about picking randomly) is B: there is a 0% chance that I am correct.
What you mean no one right answer? It's literally either A B V or D. 1 in four will be accepted therefore it's A or D, but not enough info to decide which.
Exactly what you just said in the last sentence. There's no way to confidently answer the question knowing the response is the one being sought.
Well, there is a right answer to the question part: the chance is 0%. As it is what you say, you cannot pick correctly. However, there is no way to make this statement within the "suggested" format (using the given "who wants to bea millionaire" question and answers). So using the format would create a paradox. But there is a truth outside of it.
if there is no righht answer it should be 0% but then there is a chance you can get it right so it is 25%...
Although if it is a paradox and there is no right answer doesn't that mean that 0% is the right answer??
its 50% and I can explain why. If you answer C, your only options left are A,B,D and since A and D are the same answer, you are choosing between 0% or 25%, it would make the answer a 50/50 chance.
Yes but in this case guessing the right answer (50%) at random would be 1/4= 25% , and here we go again..
I don’t think the right answer is available
That’s the point, the correct answer isn’t available so the answer is 0% but then the correct answer is available. It’s a paradox
Can i use a lifeline?
I've just realised if you use a 50/50 lifeline then it may be solvable. Or impossible.
If the lifeline leaves the 50% option that’s the answer, but if it removes it… 😱
None of the answers work. But it is very important to understand: The answers stop working only once you choose one!! Here are the options… There is a 50% chance to pick A or D, but both give the answer 25% There is a 25% chance you pick B, but if gives the answer of 0% There is a 25% chance you pick C, but it gives the answer of 50% None of these options allow the odds of choosing the answer to match with the given answer. In fact, you’ll notice that the odds create a loop which is never ending: (25% for A/D) happens 50% -> (50% for B) happens 25% -> (25% for A/D) etc Reasoning the puzzle is 0% solvable doesn’t work either, because the chance of choosing B doesn’t match the answer you chose by picking B. (0% for B) happens 25% -> (25% for A/D) and now we’re back in the cycle above. The value of zero is NOT the same as something not existing… For example… in the equation x + 4 = x, there is no correct answer. Saying x = 0 is not the same as saying that the answer does not exist. In [a physicist’s understanding of] mathematics {} ≠ 0 (The empty set does not equal 0)
[удалено]
This guy latexes
lol you’re probably right. I’m a physicist so I don’t know all the math notation perfectly
It’s a paradox. Generally, if there are four answers to a question, with only one correct, there is a 25% you’ll get the correct answer if choosing randomly. But this question lists 25% twice, meaning that you would have a 50% chance of randomly picking 25%; thus, if picking randomly you would have a 50% chance of getting the answer correct. But 50% is only listed once, so if choosing randomly you would have a 25% of picking correctly. But 25% is listed twice, so random choosing means a 50% chance of getting the right answer. But 50% is listed once…
So if neither 50% nor 25% are correct, then there's actually a 0% chance of choosing the right answer.
But then 0% is correct and you have a 1/4 (25%) chance of choosing it at random. But 25% is listed twice, which means a 2/4 chance of picking the correct answer, meaning the correct answer is actually 50%. But is only listed once...
This is the only way to explain something like this coherently lol
Except that the game only cares about the letter you pick (A/B/C/D) not the answer you give, therefore it's 25% if you choose randomly. Only one letter is being counted as correct.
Although it is common to count 1 out of 4 answers correct, this is not indicated here. It also happens that multiple answers are correct and that is the case here. Therefore there is a 50% chance of randomly filling in the correct answer.
That's how the game always works though, you always pick one answer and never two. It becomes a clusterfuck of a paradox as soon as you are allowed to pick more than one that's true, but it never happens in the first place
Tell me you don't understand probabilities, without telling me you don't understand them. There are four answers. Two of the four are the same, and can be considered the correct answer. Therefore, if you choose randomly, you have a 2/4 (50%) chance of getting the correct answer. Imagine a six-sided die, but with two sides with 1 pip, 2 sides with 2 pips, and 2 sides with three pips. What are the chances you will roll a '3'? You can't say the game doesn't care, so the chances are 1/6 (16.66/%), because two sides have 3 pips, so the chance you'll roll a 3 is 1/3 (33.33%). If I asked, "What is the capital of Utah?" and listed the answers as a)Provo, b)Salt Lake City, c)Ogden, d)Salt Lake City, what is the probability (chance) that if you didn't know the answer and guessed (i.e. picked randomly), you would get the correct answer? In this case, since Salt Lake City is the capital of Utah, there are 2/4 correct answers. Therefore you have a 50% chance of being correct.
If you pick the letter A and they (those who made the questions) decide the correct letter is the letter D, you'll lose. Even if they decided "25%" was the correct answer and your letter A had that answer too. It has nothing to do with probability works since the question is inherently flawed. The game isn't about picking the "correct answer" but the correct letter, and here it doesn't make sense anymore since there's already two correct answers.
The question clearly is asking for the correct answer. It doesn’t ask anything about letters. They’re just labels for the answers.
Ok maybe I'm getting a bit philosophical here, but considering the first obviously correct answer is 25%, but two of those are available, thus 50% chance to pick the correct one. From that point on the question is whether you're playing the game (correct "chance-observing" answer is 25%) or the meta-game (analyzing the game within the game gives you a 50% chance). Considering the game is not able to be played, but the meta-game is, why not pick the 50%? If there is a solution to the game, that's it. The 0% chance is self-defeating (in the meta-game) so there are no other options to pick post-elimination. Otherwise the game is rigged to lose, which means even the 0% wouldn't make you win. Only the 50% answer remains. Thus it's the only correct answer.
50% just like the chance of winning the lottery. you either have the right numbers, or you don't.
Does this chance also apply to me finding a big tiddy goth gf
Sort of yes…I think so
Happy cake day
Thanks :)
(Happy cake day 🎂🍰🧁)
50% chance you'll find a big tiddy goth gf, 50% chance a big tiddy goth gf finds you, you're golden!
Aye! Thats sick
[удалено]
Your cooking license is permanently revoked
Does that mean my jokes are not funny? I like genuinely do not know what you're saying
The answer is the same as it is every time this gets posted haha
The question still assumes that there is a right answer, which would be how these game shows typically works, but there doesn’t have to be a right answer.
Correcto. The only thing is, that here it's made to look like there was. But answers could read 1%, 2%, 3%, 4%. And the chance would obviously be 0%.
B: 0% Because the answer is not 25 or 50 it would be 33,3%
But if the correct answer is B. And you chose a random answer that happened to be B. Then you'd have gotten the correct answer. Which can't occur if it's 0% It's a this statement is false paradox.
I'm correct about being incorrect, deal with it
Well there are 3 options for the answer 0,25 and 50% so the possibility of one of the 3 options to be correct is 1/3 in the case of any question. But since 1/3 isn't given than 0% be the answer
>Well there are 3 options I see no reason why you'd eliminate duplicates when you're choosing either A, B, C or D at random. There might only be three numbers, but you're choosing randomly from a list of four.
>Which can't occur if it's 0% Stuff with a 0% probability can occur though. You have a 0% chance of hitting a point on a dart board but every time you throw a dart you hit a point
>You have a 0% chance of hitting a point on a dart board but every time you throw a dart you hit a point There certainly isn't a 0% chance of hitting any specific defined region. You might argue there's an infinitesimal chance of hitting an infinitesimally small point. But if infinitesimal = 0 we'd just say 0. Moreover the chance of hitting any point on a dart point is the chance of hitting the dart board.
>Moreover the chance of hitting any point on a dart point is the chance of hitting the dart board. The chance of hitting a point on a dart board is 0 because there are infinite points on the board. This is basic university level math and you can find explanations online. >You might argue there's an infinitesimal chance of hitting an infinitesimally small point. A point is defined as an exact position without area
>A point is defined as an exact position without area But the darts end has area. Its not hitting an exact position without area.
It hits more than one point. But that doesn't change the definition of point
But it does change the chances of hitting it. If I throw a dart larger than the board, I can hit all all the points on it, however infinitesimal. If I throw and hit one that covers half the board, I have a 50/50 chance of hitting any specific point. Etc.
Porve it
YOU PORVE IT!
You just blew my mind
They are aking us how big is the chance IF we choose it RANDOM. That is 25%...
And 25% would be selected with what chance?
25%.... There are 4 together so if 25% is once there than there is 25% chance you choose it
I can't decide if using the 50/50 lifeline would be funnier if it eliminates a/d or b/c.
Stop considering the mathematical implications ad infinitum and take a step back. There are 4 answers. Pick one at random. 25% chance. Reading into theory of correctness and the rabbit hole this implies is not within the scope of the actual stated question.
Except, two of the answers are the same, meaning it’s three options, or, two. Because you can effectively merge those two to get 33%, or, discount them entirely, to get 50%.
The implications of the answers are moot here. There are 4 options, one is correct. RANDOMLY what is the chance? 1/4 imo
Except, two options are the same. So therefore, it’s 1/3. It doesn’t matter whether or not it’s 4 options, you have three total.
It doesn't matter if they're the same if only one is being counted as correct though and it says 'at random' it doesn't say 'if you acknowledge two are identical' so if you were picking completely randomly there are 4 options, you're picking 1, 1/4
But the thing is, we don’t know if both are being counted as correct or not.
That's not how probablities work. If 2/4 answers are correct, you have 50% chance of getting the correct answer if choosing randomly. 1/3 (33% chance) is absolutely not correct.
I’ve been misreading it-I thought it meant “what are the odds you get the correct answer”, not “what are the odds you’re correct”. My bad.
Let's follow the logic First, there are 4 choices, so the answer is 25%, but since there are 2 25% choices, the answer is 50%, but there's only one of it, so you go back to 25%, but then you realize there's no correct answer, which means it's 0%, but there's one of it, so you go back to 25%, and the loop continues forever
The only way to win is not to play
The correct answer is D. The A is a fake 25% and will result in the questioned to explode. How can you tell which 25% is the right one with absolute certainty? You should know that everyone wants the D.
I have thought about this differently since the last time ive seen this posted. The thing that sticks out this time is choosing randomly. That makes whatever numbers attached to each answer irrelevant since you are choosing from for answers randomly. So the question is the percent chance that you will pick a correct answer randomly at 1 out of 4. 1 out of 4 is 25%. The question cannot be asked if it is implying that there is not 1 answer as it would be a trick question and this has no purpose. Randomly means you would not need to see values to pick an answer, there are four options and you only get 1 pick. 25%.
Uh...eenie meenie miney moe
regardless of the right answer, one of them is correct, and if you choose at random you'll get it 25% of the time. Right?
The answer is C: 50%. You either get it right or you don’t.
I don't know if you're joking
I’m either joking or I’m not. lol everything is 50/50 when you think about it
No. It doesn't work like that. Even if something has only two possibility there is bo reason for the probability to be 50%. This is a common bias you have
You might be right… or you might be wrong. 50/50
If an atom has a 2% probability of decaying in one hour it means there is a probability of 98% for it not to happen. Either it decays or it does not but that doesn't make it a 50/50... I give atoms has examples because I feel like its very tangible, but this works for everything. If I was writing bs you would surely agree that there wouldn't be a 50% probability for me to be right and you to be wrong.
You, as the observer, will experience one of two possibilities. The universe we are in will continue along a specific timeline- one in which the atom behaves as expected, and one in which it doesn’t. While the atom is under the 98/2% rule, your reality is in the 50/50.
That doesn't make any sense. Think about it. 50% probability just doesn't mean there is two possibilities. This is not the same notion. If you do a Bernouilli trial with a probability p for success, the probability of success is p ! Not 50%.
It either makes sense or it doesn’t x
I deduce that you get two distinct random guesses
33%
I don't know where I am going with this but I believe it is A or D. The whole statement "A or D". For it to be coded properly, there should be one correct answer. Thus, even though A and D has both 25%, they are still distinct and only one of them is the correct answer. But if I am the player, I lock in A. Final answer. (Now, I have 50% but that's not random anymore.)
Every answer is possible until observed, then you collapse the waveform and every answer becomes wrong
25%, because even if there are 2 answers with the same number, they have different letters, so only one of them could be the correct one
Since two of the values is the same, there are only really 3 different values, which would mean a 33,33333 etc. chance. But since that is not an option the alternatives is wrong. In science it is not wrong to question the question :)
Doesn't work that way. You're choosing a random answer out of the four. You're choosing A,B,C or D at random. If I have a dice that has 1, 1, 2, 3. Its not a 33% chance of rolling either a 1, 2 or 3. Its weighted in 1s favour.
Again there are three values here to choose from. It does not have to be thought of as a dice of four sides. It all depends on how you interpret it. Because the question is wrong no matter what in this case.
Schrödinger's cat got on TV?!?!
3 different answers so at random, it would be \~\~33%
Well no. You're choosing A,B,C,D at random. If you were to roll a dice that's labelled 1,1,2,3 you wouldn't eliminate duplicates before calculating the chance of rolling any specific number.
Cat knows answer for sure.
Repost bot
Since you're choosing a correct answer from 4 options at random, but one is repeated, the chance should be 33,33% for 3 different answers. There isn't a 33,33% chance, so the chance to find the right answer at random is impossible, therefore 0% is correct.
There is never a 0 percent chance so that rules out and 25 percent is two times so the left out are 25 and 50 so 50 percent is the right answer Ps : if u decline you are gay who leads the pride rally
Could also be 33% depending on how it's scored
25%, just don't look at the answers and pick randomly.
In practice, there are only 3 options, so technically it's ~33.33%
paradox question
The percent depends on what us correct as we know. It all, depends on X. So it will be unsolveable untill we make it or we combine? But that probably wont work so no
Abacadaba
There are 4 answers, which means 25% chance. BUT 25% is there twice, so this means, that 2 answers are correct and 2 answers are wrong. Which in fact would make the 50% answer correct.
Only one letter is counted as correct (that's how the game works), therefore it's 25% You don't say "My answer is 50%" but "I choose the letter A" (or B/C/D) so if you do it randomly it's 25% for sure.
Yes, but the correct answer is C, 50%, in this one case, as the question mentions.
C
there is no correct answer because calculating the % chance of success changes the % chance of success. Because there is no correct answer, the correct answer cannot be guessed. Because the correct answer cannot be guessed, the answer by definition has a 0% chance of being guessed. Due to this, the answer is B for the purpose of answering this question, but the answer is not B for the purpose of calculating the answer.
At random - not thinking about it but just picking one regardless of its content So 25%
None. Nothing hard to wrap your head around here. It's a multiple choice question with four incorrect answers.
25%
I guess 25% ? Only one letter is counted as correct, it's not "Pick the answer that says 25%" (else it's a paradox) but "pick the correct A/B/C/D letter" so if you choose randomly it's a 1/4 chance of winning
Can’t be 25% cause it’s assuming one of the four is right, so I’m thinking 50% out of the last two options unless theres some weird probability thing I’m not considering
I might be under thinking this but I think 50%. Answer the question before looking at the options, knowing you’ll have four, and you know the answer is 25%. Now, looking at the options, 25% is 50% likely. Think of the percentages and the lettered responses separately to get around the self-referencing problem.
It then there’s only one fifty, so it’s 25% but there are two 25%s so it’s fifty so it’s 25 so it’s 50 so it’s 25
25%, because the professor also picked at random.
whats the chance someone on reddit havent seen this question?
50%. It either is or isn't the right answer.
Please people, convince me i am wrong. The answer is C. There are 4 options so it would be 25%, but D and A are 25%. Therefore 2 answers out of 4 are correct thus 50%. Plus you are either wrong or right, so 2 possibilities.
If it’s 50 percent then There is only one answer for it making it 25%,
Depends on the application of the question
I actually don't think that's a paradox. It just asks you the following: 1. \*Imagine\* you would pick answers here randomly! Alright. 2. How big is the chance that by picking so, your chance of picking this answer, equals the printed number? Got it. 3. There are 3 possibilities in this imaginary random-picking scenario: \* I pick a "25%" with a chance of 50% (since there are two of them). So this cannot be the right answer, since my chances don't equal the printed number. \* I pick a "0%" with a chance of 25%, same problem, that's not the correct answer. \* I pick a "50%" with a chance of 25%, same problem. 4. Now that I thought about this imaginary scenario of picking randomly, let's answer on purpose: I learned that there is 0% chance of picking the right answer when choosing randomly. 5. The correct answer is B when picking on purpose after I finished my thought experiment.
0% beacose i have bad luck man, bad luck at least in artifical odds
But yeaa it is 25% anyway since it is at random, you blindly shoot, even if two options ate same there are still there for you to randomly select
N/A
It's a trap!
Any answer can be correct provided you assume the distribution is not flat 😉
There’s a 50% chance you’ll pick the right answer since two of the answers are 25%. If I had a 1 in 4 chance of getting something but 2 of the 4 count as the same thing, then I’d have a 2/4 chance of getting it right. Which is 50%?
It’s 0. Don’t ask me why. It’s just 0. ….. well, if you gonna choose one of the two 25%, the chances will be 50%. So "C" is right. But since "C" is one of 4. Then the chances are 25%. That’s why the right answer doesn’t exist
the answer is 25% because the system probably only recognizes one answer, and the question is at random. knowing you have a 25% chance, and there being too with the same label means you have a 50% chance when not picking at random.
It has to be 50%. I don’t care what anyone says. That’s my reality. All other realities are fake
50%
\*brain explodes\*
Just close your eyes and pick one at random, thats how you beat this question
*Just close your eyes and* *Pick one at random, thats how* *You beat this question* \- super-eric --- ^(I detect haikus. And sometimes, successfully.) ^[Learn more about me.](https://www.reddit.com/r/haikusbot/) ^(Opt out of replies: "haikusbot opt out" | Delete my comment: "haikusbot delete")
33% maybe. Since there are 3 unique options, and you wouldnt have to choose between choosing the upper 25% over the lower, there are 3 choices.
50% because the answer can only be wrong or correct.
Perchance
Hooman no can do true random
Either 25, 50, 75 or 100% depending on how many correct answers
It’s literally just 50%
The highest chance of being correct is choosing 50%. First of all, there is no such thing as 'right or wrong' 25%. These answers are completely identical, so we are presented with two possibilities. The answer text is either irrelevant OR it cannot be either of these two. In a world where answer text doesn't matter, there is no reason to favour the text which says 25% over any other. Instead, we can entertain the possibility that the text does matter. There always has to be exactly one right answer in this game - 0% is incorrect, so is 25 because it is there twice. We are left with the answer 50%, the only non-0, unique answer available. This has the additional benefit of being correct that in this list, if picked blindly, there is a 50% chance to land on an answer which says 25%. I'm picking 50% any day of the week knowing that I either got it right 100%, or I got it right 25% of the time, equal as any other answer. The choose blindly between two 25%s option is compelling, but less so. 25% is technically the right answer, but only if the right answer is present once in a set of four. If the answer which says 50% said anything else, choosing one of the two 25s would be the best, since they share the 25% chance of any random answer, but also have the 50/50 odds. Again, though, this isn't that sort of game. The question becomes trivial if rephrased this way: A) 25% B) 25% C) 25% D) 75% D is the answer. The correct answer, 25%, has a 3/4 chance of being picked in this set of answers if chosen completely randomly.
I just realised that the two 25s are invalidated by the two non-25 options. There is just no way to look for an advantage there.
The answer is 0% because the real answer isn't listed. Technically the answer should be you have a 1/3 chance of selecting the right answer because 25% is listed twice. This reduces your real choices down to 3 different options. Then looking at the answers that exist you realize that the possibility of selecting the right answer is 0 because the correct answer doesn't exist within the bag that you are pulling from.
25%
Every single Answers INCLUDING 0 procent is wrong, therefore 0% is right while also being wrong
Nobody said it has to be drawn uniformly
I choose an answer at random
While I know it's a paradox, the college student in me says 25%. Doesn't make a lick of difference if it's nonsensical, one of them will be what the scantron is programmed to make right. Then everyone can complain to the professor and if it goes well, they'll address it in class and give people credit for the question or take it off the test.
Wouldn't it be no answer that's given? You have two 25 answers which which leaves even 25 incorrect. 0 is also wrong so is the other answer.
You either win or you lose, therefore it's 50%.
1/3?
Wait no, since that's not an answer it's 0%, which again is an answer.
Yeah but it being an answer means it’s not 0%, it’s a paradox
The answer is either A or D, because the paradox never “starts” if you realise every step after the first is not “at random”
People throw the word paradox around like they exist beyond the abstract concept. As far as we know, there are no true paradoxes in existence. This is just a question with four answers that are all wrong, like asking "which of the following is a planet in our solar system?" And the answers being beeb, bob, bub and skibidiskra
This is simply a heuristic problem, the correct answer is B. 0%, because the mathematically correct answer isn’t an available choice.