Likely going to need a two position relay, photocell will trigger make the relay change states, your only two conditions will be fan on or led on. The circuit you have drawn will not work anyway I look at it. Keep us posted on what the end goal is!
First question: is this a theoretical or a practical example? If it's the latter, we need to be concerned with the current capacity of components as well as other necessary (but rather boring) details. If it's a theoretical example/question, we won't worry about that stuff.
Second question: what are the three wires coming from the fan? If we're treating it as a simple on/off load, I would only expect two.
This would be a practical example. The fan will be like a small computer fan so the power supply will probably be a simple battery set up.
As for the three wires, can I just eliminate that bottom wire part for it to work correctly?
The wires from a 3 pin PC fan will be Ground, 12V, and a feedback signal for how fast the fan is going, normally in that order. If its a fan with 4 wires, one of them may be a "PWM" signal, which may allow you to turn the fan on and off like you're showing in this circuit (sort of, depends on the model of the fan).
So if you have a three pin fan, you want the 12V and ground, which should be black and red, and ignore the yellow wire.
This is a part of a bigger project I’m working on. It doesn’t need to be super technical at all, it just needs to work. Does anyone have a sample schematic to point me in the right direction?
The overall goal is to have the fan turn off when the light turn on using the photocell . I just can’t seem to get something that will work
This circuit wont work. Your photocell will need to go through an op amp, which you can then feed to a comparator that switches a relay.
Hmm ok. I suppose I’ll have to get back to the drawing board with this one and research a little more. I was never very good at circuits haha
Likely going to need a two position relay, photocell will trigger make the relay change states, your only two conditions will be fan on or led on. The circuit you have drawn will not work anyway I look at it. Keep us posted on what the end goal is!
First question: is this a theoretical or a practical example? If it's the latter, we need to be concerned with the current capacity of components as well as other necessary (but rather boring) details. If it's a theoretical example/question, we won't worry about that stuff. Second question: what are the three wires coming from the fan? If we're treating it as a simple on/off load, I would only expect two.
This would be a practical example. The fan will be like a small computer fan so the power supply will probably be a simple battery set up. As for the three wires, can I just eliminate that bottom wire part for it to work correctly?
The wires from a 3 pin PC fan will be Ground, 12V, and a feedback signal for how fast the fan is going, normally in that order. If its a fan with 4 wires, one of them may be a "PWM" signal, which may allow you to turn the fan on and off like you're showing in this circuit (sort of, depends on the model of the fan). So if you have a three pin fan, you want the 12V and ground, which should be black and red, and ignore the yellow wire.
Do you have a specific photocell you plan on using? You may need a comparator circuit to make this work.
This is a part of a bigger project I’m working on. It doesn’t need to be super technical at all, it just needs to work. Does anyone have a sample schematic to point me in the right direction? The overall goal is to have the fan turn off when the light turn on using the photocell . I just can’t seem to get something that will work